Find the number of atoms in 7.85 g of aluminum
MM(Al) = 26.98 g/mol
n(Al) "= \\frac{7.85}{26.98}= 0.29 \\;mol"
A mole of Al contains 6.02×1023 atoms.
N(atoms)"= 0.29 \\times 6.2 \\times 10^{23}=1.8 \\times 10^{23} \\; atoms"
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