Answer to Question #199458 in Inorganic Chemistry for someone

Question

At standard temperature and pressure, how many L of fluorine gas (F₂) are there in 3.01 mol of it?

• 1.34 × 10^–1 L of F2
• 1.14 × 10² L of F₂
• 6.74 × 10¹ L of F₂
• 7.92 × 10^–2 L of F₂

_{which of the options ?}

Answer 1

The no of litres found in 3.01 moles of fluorine=68.32241L

Given:

Moles of fluorine=3mol

To Find:

No of litres present in 3mol of Fluorine.

Step by Step by Explanation:

Formula used for calculating the volume of fluorine is achieved through ideal gas equation

According to Ideal Gas;

From this above equation, volume can be calculated as

Where V=Volume of the fluorine in litres

N=number of moles=3.01moles

R=Gas constant

Under standard conditions

T=Temperature of the gas=273K 

P=Pressure of the gas

Substitute all the values in the above equation we get

Result:

Thus the no of litres found in 3.01 moles of fluorine gas is 68.32241L

= 6.74 × 10¹ L of F₂