The pressure applied by a boy on a bicycle pump was 2 Pascal. If the volume was increased to 2/3 the initial volume. Calculate the final pressure.
Initial pressure, P1=2 PaP_1=2\space PaP1=2 Pa
Initial volume, V1=VV_1=VV1=V
Final pressure, P2=PP_2=PP2=P
Final Volume, V2=V+23V=53VV_2=V+\dfrac{2}{3}V=\dfrac{5}{3}VV2=V+32V=35V
P1V1=P2V2P_1V_1=P_2V_2P1V1=P2V2
P=P1V1V2=2×V53VP=\dfrac{P_1V_1}{V_2}=\dfrac{2\times V}{\dfrac{5}{3}V}P=V2P1V1=35V2×V
P=1.2 PaP=1.2\space PaP=1.2 Pa
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