Question

2 Al + 6 HBr à 2 AlBr3   +  3 H2

 

3.22 moles of Al are reacted with 4.96 moles of HBr, and 1.96 moles of H2 was produced.

a. What is the limiting reagent?

b. Calculate the percent yield of H2.

 

Answer 1

a) $H Br$ is the limiting reactant

b) Percent yield of H2=49.5%