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Answer to Question #19480 in Inorganic Chemistry for Aneta
Question #19480
If 96.5 moles of an ideal gas occupies 41.5 liters at 301 K, what is the pressure of the gas?
Expert's answer
PV = nRT
P = nRT/V
P = 96.5*8.31*301/41.5 = 5816,3 kPa
P = nRT/V
P = 96.5*8.31*301/41.5 = 5816,3 kPa
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