What is the pH of 0.12 M NH3 ?
Lütfen birini seçin:
a. 8.88
b. 6.88
c. 1.84
d. 12.16
e. 7.88
Ans:-
pH of 0.12M0.12 M0.12M NH3NH_3NH3
⇒pH=−log[M]⇒pH=−log[0.12]⇒pH=\Rightarrow pH=-log[M]\\ \Rightarrow pH=-log[0.12] \Rightarrow pH=⇒pH=−log[M]⇒pH=−log[0.12]⇒pH= 1.84
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