Question #19174

How much energy must be absorbed by a 150 g sample of ice at 0.0 degrees celcius that metls and then warms to 25.0 degrees celcius?

Expert's answer

1. How much energy must be absorbed by a 150 g sample of ice at 0.0 degrees Celsius that melts and then warms to 25.0 degrees Celsius?

**Solution.**


Q1=mλQ_1 = m \cdot \lambdaQ2=cm(tt0)Q_2 = c \cdot m \cdot (t - t_0)E=Q1+Q2=mλ+cm(tt0)E = Q_1 + Q_2 = m \cdot \lambda + c \cdot m \cdot (t - t_0)


Given: m=0.15kgm = 0.15 \, \text{kg}, t0=0Ct_0 = 0^\circ \text{C}, t=25Ct = 25^\circ \text{C}, tt0=25Kt - t_0 = 25 \, \text{K}, λ=335000Jkg\lambda = 335000 \, \frac{\text{J}}{\text{kg}}, c=4183JkgKc = 4183 \, \frac{\text{J}}{\text{kg} \cdot \text{K}}

Find: E?E - ?

E=0.15kg335000Jkg+4183JkgK0.15kg25K66kJE = 0.15 \, \text{kg} \cdot 335000 \, \frac{\text{J}}{\text{kg}} + 4183 \, \frac{\text{J}}{\text{kg} \cdot \text{K}} \cdot 0.15 \, \text{kg} \cdot 25 \, \text{K} \approx 66 \, \text{kJ}


**Answer:**


E=66kJE = 66 \, \text{kJ}

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