1. How much energy must be absorbed by a 150 g sample of ice at 0.0 degrees Celsius that melts and then warms to 25.0 degrees Celsius?
**Solution.**
Q1=m⋅λQ2=c⋅m⋅(t−t0)E=Q1+Q2=m⋅λ+c⋅m⋅(t−t0)
Given: m=0.15kg, t0=0∘C, t=25∘C, t−t0=25K, λ=335000kgJ, c=4183kg⋅KJ
Find: E−?
E=0.15kg⋅335000kgJ+4183kg⋅KJ⋅0.15kg⋅25K≈66kJ
**Answer:**
E=66kJ