If 4.70 grams of hydrogen sulfide react, how many grams of sulfur dioxide will be
produced?
The equation of the reaction between the hydrogen sulfide and oxygen is:
2H2S+ 3O2 ↔\leftrightarrow↔ 2SO2 + 2H2O.
Moles of H2S=4.7034.1=0.138molesH_2S= \frac{4.70}{34.1}= 0.138molesH2S=34.14.70=0.138moles
Moles of SO2=0.138SO_2=0.138SO2=0.138
Mass of SO2=0.138×64.066=8.841gramsSO_2= 0.138×64.066= 8.841 gramsSO2=0.138×64.066=8.841grams
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