Question

If 4.70 grams of hydrogen sulfide react, how many grams of sulfur dioxide will be

produced?

Answer 1

The equation of the reaction between the hydrogen sulfide and oxygen is:

2H₂S+ 3O₂ $\leftrightarrow$ 2SO₂ + 2H₂O.

Moles of $H_2S= \frac{4.70}{34.1}= 0.138moles$

Moles of $SO_2=0.138$

Mass of $SO_2= 0.138×64.066= 8.841 grams$