What is the mass of 8.30x1024 molecules of NH3?
The molar mass of NH3 is 17.03 g/mol
1 mole of anything contains Avogadro's number of particles (6.022 x 1023). Therefore,
m(NH3)=8.30×1024molecules×1mol(NH3)6.022×1023molecules(NH3)×17.03g(NH3)1mol(NH3)=235gm(NH_3)=8.30\times10^{24}molecules\times\frac{1mol(NH_3)}{6.022\times10^{23}molecules(NH_3)}\times\frac{17.03g(NH_3)}{1mol(NH_3)}=235gm(NH3)=8.30×1024molecules×6.022×1023molecules(NH3)1mol(NH3)×1mol(NH3)17.03g(NH3)=235g
Answer: 235 g
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