What is the mass of 8.30x1024 molecules of NH3?
The molar mass of NH3 is 17.03 g/mol
1 mole of anything contains Avogadro's number of particles (6.022 x 1023). Therefore,
"m(NH_3)=8.30\\times10^{24}molecules\\times\\frac{1mol(NH_3)}{6.022\\times10^{23}molecules(NH_3)}\\times\\frac{17.03g(NH_3)}{1mol(NH_3)}=235g"
Answer: 235 g
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