Question

Na₂CO₃ (aq) + CaCl₂ (aq) = 2 NaCl(aq) + CaCO₃ (s)

Calculate the volume (in mL) of 0.100 M CaCl₂ needed to produce 1.00 g of CaCO₃ (s)

there is an excess of Na₂CO_3.

Molar mass of calcium carbonate = 100.09 g/mol

Answer 1

$Moles ( CaCO_3)= \frac{1.00}{100.09}=9.99moles$

$Volume =\frac{9.99}{0.100}= 99.9 cm^3$