Question

how many grams of nitrogen dioxide is required in this reaction to produce 5. grams of HNO3

Answer 1

 

3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)

Mass of $HNO_3 = 5grams$

Molar mass: 63.01 g/mol

Moles of $HNO_3= \frac{5}{63.01}=0.079$

Moles of $NO_2 = \frac{3×0.079}{2}=0.1185 moles$

Mass of $NO_2 = 46 × 0.1185=5.451grams$