how many grams of nitrogen dioxide is required in this reaction to produce 5. grams of HNO3
3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)
Mass of HNO3=5gramsHNO_3 = 5gramsHNO3=5grams
Molar mass: 63.01 g/mol
Moles of HNO3=563.01=0.079HNO_3= \frac{5}{63.01}=0.079HNO3=63.015=0.079
Moles of NO2=3×0.0792=0.1185molesNO_2 = \frac{3×0.079}{2}=0.1185 molesNO2=23×0.079=0.1185moles
Mass of NO2=46×0.1185=5.451gramsNO_2 = 46 × 0.1185=5.451gramsNO2=46×0.1185=5.451grams
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