Question #18289

a hydrocarbon contains 82.7% C and 17,24% H by mass. 1 mole of hydrocarbon weighed 58g. find the molecular formula of the hydrocarbon

Expert's answer

a hydrocarbon contains 82.7% C and 17,24% H by mass. 1 mole of hydrocarbon weighed 58g. find the molecular formula of the hydrocarbon


CXHYX:Y=ω(C)M(C):ω(H)M(H)=82.712:17.241=6.89:17.24=1:2.5=2:5C4H10M=124+110=58g/mol\begin{array}{l} C _ {X} H _ {Y} \\ X: Y = \frac {\omega (C)}{M (C)}: \frac {\omega (H)}{M (H)} = \frac {8 2 . 7}{1 2}: \frac {1 7 . 2 4}{1} = 6. 8 9: 1 7. 2 4 = 1: 2. 5 = 2: 5 \\ C _ {4} H _ {1 0} \\ M = 1 2 * 4 + 1 * 1 0 = 5 8 g / m o l \\ \end{array}C4H10\mathbf {C} _ {4} \mathbf {H} _ {1 0}

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