Question #18288

a cylinder of bottled gas contains 47 kg of propane, C3H8. how many propane molecules does it contain

Expert's answer

a cylinder of bottled gas contains 47 kg of propane, C3H8. how many propane molecules does it contain


ν(C3H8)=47×10344=1.07×103 mol\nu (C3H8) = \frac{47 \times 10^3}{44} = 1.07 \times 10^3 \text{ mol}N=1.07×103×6.02×1023=6.4414×1026N = 1.07 \times 10^3 \times 6.02 \times 10^{23} = 6.4414 \times 10^{26}

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