Question

an organic compound contains 66.7% C, 11.1% H and had a remainder is oxygen. it relative formula mass was 72. find the empirical formula of the compound and the molecular formula of the compound

Answer 1

an organic compound contains 66.7% C, 11.1% H and had a remainder is oxygen. it relative formula mass was 72. find the empirical formula of the compound and the molecular formula of the compound

$$\omega(O) = 100 - 66.7 - 11.1 = 22.2\%$$ $$C_X O_Y H_Z$$ $$X: Y: Z = \frac{\omega_1}{M_1}: \frac{\omega_2}{M_2}: \frac{\omega_3}{M_3}$$ $$X: Y: Z = \frac{66.7}{12}: \frac{22.2}{16}: \frac{11.1}{1} = 5.56:1.39:11.1 = 4:1:8$$ $$12*4 + 1*16 + 8*1 = 72 \rightarrow \mathbf{C}_4\mathbf{H}_8\mathbf{O}$$