Answer to Question #18238 in Inorganic Chemistry for sean

Question

calculate the mass of butane needed to produce 53.9 grams of carbon dioxide

Answer 1

2C₄H₁₀+ 13O₂ = 8CO₂ + 10H₂O;
n(CO₂) = 53.9g/44 g/mol
n(CO₂) = 1.225 mol;
n(C₄H₁₀) = 0.30625 mol;
m(C₄H₁₀) = 0.30625 mol * 58 g/mol = 17.7625 g