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Answer to Question #18203 in Inorganic Chemistry for Ay
Question #18203
Identify the element being oxidized and the element being reduced in the following reaction: P4(s)+5O2(g)->P4O10(s)
Expert's answer
P40(s) + 5O20(g)= P4+5O10-2(s)
P40 – 20е = 4P+5 20 4 1 -oxidized
O20 + 4е = 2O-2 4 20 5 - reduced
P40 – 20е = 4P+5 20 4 1 -oxidized
O20 + 4е = 2O-2 4 20 5 - reduced
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