Question

How many moles of lithium phosphate are in
90.2 g of this substance?
Answer in units of mol

Answer 1

How many moles of lithium phosphate are in 90.2 g of this substance?

Answer in units of mol

$$\mathrm{M(Li(PO_4)_3)} = 7 + (31 + 64) * 3 = 292 \ \mathrm{g/mol}$$ $$\nu = \frac{m}{M}$$ $$\nu = \frac{90.2}{292} = 0.31 \ \mathrm{mol}$$

0.31 mol