Answer to Question #179065 in Inorganic Chemistry for Sky

Question

A sample of water contains: suspended matter = 100 mg; Ca(NO3)2 = 16.4 mg/L; MgSO4 = 24 mg/L; MgCl2 = 19 mg/L; NaOH = 40 mg/L and KOH = 56 mg/L. Calculate temporary, permanent and total hardness of the water sample in PPM.

Answer 1

Total hardness =3 12.5 ppm

Permanent hardness =208.33ppm

Temporary hardness = total hardness – permanent hardness= 312.5 – 208.33 = 104.17ppm