Answer to Question #179024 in Inorganic Chemistry for laia

Question

A sample of CO₂ gas at 25 ºC has a volume of 15 L and exerts a pressuer of 15.6 psi. How many grams of gas are in the sample?

Answer 1

We use Ideal Gas Law;

PV=nRT

Therefore; $n=\dfrac{PV}{RT}$

Since;

P=15.6 psi (changing it to atm we divide by 14.696) = $\dfrac{15.6psi}{14.696} = 1.0615atm$

V= 15L

T= (25 + 273) = 298K

R = 0.0821atm L mol^-1 K^-1

$n= \dfrac{1.0615atm x 15L}{0.0821Latm mol-1K-1 x 298K}$ = 0.650806 moles

If moles =$\dfrac{mass}{MM}$

Mass = Moles x MM

Since MM of CO2 = 44.01g/mol

Mass = 0.0650806mol x 44.01g/mol

= 28.642g