Question #177324

Assign charges to each of the ligands and to the central cation: [Ru(PH3)4I2]2+


1
Expert's answer
2021-04-01T02:47:12-0400

[Ru3+(PH3)45+I2−]2+[Ru^{3 +} (PH_3)_4^{5+}I_2^{-} ]^{2+}


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