Question

which is the oxidation number of vanadium in the complex [VCl4(N(CH3)3)2]Cl ; does it have electrons in the d orbital;

Answer 1

V = +2

Cl4 = -1

N = (+5)3 (2)

CH3 = (-3)3 (2)

Cl = +1

= 13

The vandium has electrons in d orbital