Question

Calculate the pressure exerted by 0.0153 moles of CO2 gas in

a container of 1.467 L at 20.0 C.

Answer 1

$P=\frac{mRT}{MV}$

R=8.31J mol/L

M= 44 g/mol=

V=2L

T=20 C=293.15 K

$m=M\times n=44\times0.0153=0.6732$ g=0.0006732

$P=\frac{mRT}{MV}=\frac{6.732\times10^{-4}\times 8.31\times293.15}{44\times10^{-3}\times 1.467}=31.61$ mPa