Calculate the pressure exerted by 0.0153 moles of CO2 gas in
a container of 1.467 L at 20.0 C.
"P=\\frac{mRT}{MV}"
R=8.31J mol/L
M= 44 g/mol=
V=2L
T=20 C=293.15 K
"m=M\\times n=44\\times0.0153=0.6732" g=0.0006732
"P=\\frac{mRT}{MV}=\\frac{6.732\\times10^{-4}\\times 8.31\\times293.15}{44\\times10^{-3}\\times 1.467}=31.61" mPa
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