Answer to Question #170804 in Inorganic Chemistry for Alex

Question

Iron (III) chloride reacts with magnesium oxide. If 13.75 g of iron (III) chloride reacts with magnesium oxide to form 5.25 g of the magnesium product, what is the percent yield?

Answer 1

$2FeCl_3+3MgO=Fe_2O_3+3MgCl_2$

m(MgCl₂) = M(MgCl₂)×n(MgCl₂)

n(MgCl₂) = 3/2 n(FeCl₃) = 3/2 m(FeCl₃)/M(FeCl₃)

m(MgCl₂) = 3/2 M(MgCl₂) m(FeCl₃)/M(FeCl₃) = 12.11 g

Yield = 5.25/12.11 × 100% = 43.35%