Question

Copper (II) sulfide reacts with oxygen gas to produce copper (II) oxide and sulfur dioxide. What is the balanced equation? If 100.0 g of copper (II) sulfide and 56.0 g of oxygen are available, what mass of copper (II) oxide is formed? Identify the limiting reactant. Include balanced equation, molar mass values, dimensional analysis, and limiting reactant.

Answer 1

We have the given reaction,

$2CuS + 3O_2\rightarrow2CuO + 2SO_2$

Given mass of copper sulfide = 100.0 g

Given mass of oxygen = 56.0 g of

$2CuS + 3O_2\rightarrow2CuO + 2SO_2$

Hence, we can conclude that $CuS$ is the limiting reagent in this reaction.

Mass of $CuO$ formed = 15.6g

Molar mass of Limiting reagent CuS = 159.16g/mol