Write the balanced equation for the reaction between hydrochloric acid and magnesium. What mass of the magnesium product is formed when 133.77 g of hydrochloric acid reacts? Show work. Include Molar Mass Values and Dimensional Analysis.
Mg + 2HCl --> MgCl2 + H2
Molar masses:
M(HCl)=35.453+1.008=36.461g/molM(HCl)=35.453+1.008=36.461g/molM(HCl)=35.453+1.008=36.461g/mol
M(MgCl2)=24.305+2×35.453=95.211g/molM(MgCl_2)=24.305+2\times35.453=95.211g/molM(MgCl2)=24.305+2×35.453=95.211g/mol
Mass of MgCl2:
m(MgCl2)=133.77g(HCl)×1mol(HCl)36.461g(HCl)×1mol(MgCl2)2mol(HCl)×95.211g(MgCl2)1mol(MgCl2)=174.66gm(MgCl_2)=133.77g(HCl)\times\frac{1mol(HCl)}{36.461g(HCl)}\times\frac{1mol(MgCl_2)}{2mol(HCl)}\times\frac{95.211g(MgCl_2)}{1mol(MgCl_2)}=174.66gm(MgCl2)=133.77g(HCl)×36.461g(HCl)1mol(HCl)×2mol(HCl)1mol(MgCl2)×1mol(MgCl2)95.211g(MgCl2)=174.66g
Answer: 174.66 g
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