Question

If you react .994 grams of iron (III) oxide with aluminum, what mass of iron (Fe) will be produced?

                                Fe2O3   +   Al   ®   Al2O3  +  F

Answer 1

$$m_{Fe}=2m_{Fe_2O_3}\frac{M_{Fe}}{M_{Fe_2O_3}}\\ m_{Fe}=2(0.994)\frac{55.845}{159.69}=0.695\ g$$