Question #16675
3 BaCl2 + Fe2(SO4)3 ---> 3 BaSO4 + 2 FeCl3
If 25.0 grams of Barium Sulfate are produced during the reaction, how many grams of Iron(III) sulfate were used?
If 25.0 grams of Barium Sulfate are produced during the reaction, how many grams of Iron(III) sulfate were used?
Expert's answer
& x & 25.0
3 BaCl2 + Fe2(SO4)3 ---> 3 BaSO4 + 2 FeCl3
& 400 3* 233
x=400*25 / (3*233)=14.306 g
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#340153 on Dec 2023
#340153 on Dec 2023