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Answer to Question #16675 in Inorganic Chemistry for Zach
Question #16675
3 BaCl2 + Fe2(SO4)3 ---> 3 BaSO4 + 2 FeCl3
If 25.0 grams of Barium Sulfate are produced during the reaction, how many grams of Iron(III) sulfate were used?
If 25.0 grams of Barium Sulfate are produced during the reaction, how many grams of Iron(III) sulfate were used?
Expert's answer
& x & 25.0
3 BaCl2 + Fe2(SO4)3 ---> 3 BaSO4 + 2 FeCl3
& 400 3* 233
x=400*25 / (3*233)=14.306 g
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