Question

how many grams of water (is=4.184 J/g degrees celcius) will release 1367 J of heat when cooled to 45.2 degrees celcius to 36.2 degrees Celsius

Answer 1

С = 4.184 J/(g*C)
delta T = 9 C

for m = 1 and delta t=9 it is
4.184*9=37.656 j
for m=x and delta t =9 it is 1367/37.656 = 36.3 g