Question

How many moles of Fe are needed to combine with 24 moles of Cl2 by this reaction? 

Answer 1

2Fe + 3Cl₂ = 2FeCl₃

n(Fe) = $\frac{2}{3}$n(Cl₂) = $\frac{2}{3} \times$24 = 16 (mol)

Answer: n(Fe) = 16 mol.