If 25.00 mL of 4.50 M NaOH(aq) is diluted with water to a volume of 750.0 mL, what is the molarity of the diluted NaOH(aq)?
we know molarity =(wt of solutex1000)/(mol wt of solutexvol of soln in ml)
initially:
4.5="\\frac{(w\\times1000)}{(40\\times25)}"
=4.5g
now vol of soln becomes 750 ml
so molarity becomes:
"\\frac{(4.5\\times1000)}{(40\\times750)}"
=0.15M
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