Question #161224

What is the mass of sodium iodide in 50.0 mL of 2.63  10–2 M NaI(aq)?


1
Expert's answer
2021-02-09T03:36:10-0500

No.Moles(mol)=Molarity(M)xVolume(L)No. Moles (mol) = Molarity (M) x Volume (L)

Convert 50mL into liters

1L=1000mL??=50mL=0.05L1L =1000mL\newline ??=50mL\newline =0.05L

Therefore,

No of moles=2.631020.05No of moles=0.001315molsNo\ of\ moles=2.63*10^{-2}*0.05 \newline No\ of\ moles=0.001315mols


Calculate the mass of sodium iodide

Mass is calculated using the following formula,

Mass=no of molesmolar massmass=0.001315149.89g/mol=0.2gMass=no\ of\ moles*molar\ mass\newline mass=0.001315*149.89 g/mol \newline =0.2g




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS