Question

What is the mass of sodium iodide in 50.0 mL of 2.63  10–2 M NaI(aq)?

Answer 1

$No. Moles (mol) = Molarity (M) x Volume (L)$

Convert 50mL into liters

$1L =1000mL\newline ??=50mL\newline =0.05L$

Therefore,

$No\ of\ moles=2.63*10^{-2}*0.05 \newline No\ of\ moles=0.001315mols$

Calculate the mass of sodium iodide

Mass is calculated using the following formula,

$Mass=no\ of\ moles*molar\ mass\newline mass=0.001315*149.89 g/mol \newline =0.2g$