Answer to Question #159135 in Inorganic Chemistry for Daniella

Question #159135

Calculate the mass of pure sodium chloride that will yield enough hydrogen chloride gas to neutralize 25cm3 of 0.5M potassium trioxocarbonate (V) solution 


1
Expert's answer
2021-01-28T05:47:57-0500

no. of moles of K2CO3=c×V=0.5×251000=0.0125 moles\textsf{no. of moles of } K_2CO_3 = c × V = \\ 0.5 × \dfrac{25}{1000} = 0.0125 \textsf{ moles}



2HCl+K2CO32KCl+H2CO32HCl + K_2CO_3 \to 2KCl + H_2CO_3

from the reaction above, 2 moles of HCl reacts 1 mole of K2CO3.

This means that 0.025 moles of HCl reacts 0.0125 moles of K2CO3.


2NaCl+H2SO4NaSO4+2HCl2NaCl + H_2SO_4 \to NaSO_4 + 2HCl

from the reaction above, 2 moles of NaCl produces 2 moles of HCl.

This means that 0.025 moles of NaCl reacts with 0.025 moles of H2SO4.


1 mole of NaCl is 58.5g

therefore, 0.25 moles of NaCl is 14.625g



therefore, 14.625g of NaCl will yield enough HCl to neutralize 25cm3 of 0.5M K2CO3.


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