Question #158837

Propanoic acid (C2H5COOH) is described as a weak acid. Define the term weak acid.


Write a balanced chemical equation to show the dissociation of propanoic acid (C2H5COOH). Physical states must be included.

 

A solution of propanoic acid and sodium propanoate (C2H5COONa) behaves as a buffer. Describe the term buffer solution. No chemical equations are needed.


Write a balanced chemical equation to show the dissociation of sodium propanoate (C2H5COONa). Physical states must be included.

 

Explain how a solution containing propanoic acid and sodium propanoate can function as a buffer solution. Your answer must include balanced chemical equations, physical states included.


Expert's answer

(a)

Weak acids are those acids which does not dissociate completely in their constituent ions, or in other words, those acids which do not donate their all H+H^+ ions in the solution are known as weak acids.


(b)

C2H5COOH(aq)C2H5COO(aq)+H+(aq)C_2H_5COOH(aq) \to C_2H_5COO^-(aq)+H^+(aq)

(c)

A buffer solution is a solution whose pHpH remains almost unchanged when a small amount of strong acid or strong base is added to it.

An acid-buffer solution consist of a weak acid and its conjugate base whereas a basic-buffer solution consist of a weak base and its conjugate acid.

In this case, propanoic acid act as a weak acid whereas sodium propanoate act as a conjugate base making it a acidic-buffer solution.


(d)

C2H5COONa(aq)C2H5COO(aq)+Na+(aq)C_2H_5COONa (aq) \to C_2H_5COO^-(aq) +Na^+(aq)


(e)

In this case, propanoic acid act as a weak acid whereas sodium propanoate act as a conjugate base making it a acidic-buffer solution.

If we add a strong acid, say HClHCl in the solution, then most of the H+H^+ ions from HClHCl will react with C2H5COOC_2H_5COO^- ions forming C2H5COOHC_2H_5COOH resulting in very less increase in H+H^+ ions ,hence the pHpH will slightly change.

C2H5COO(aq)+H+(aq)C2H5COOH(aq)C_2H_5COO^-(aq)+H^+(aq)\to C_2H_5COOH(aq)

Also , if a strong base like sodium hydroxide is added, the hydroxide ions from NaOHNaOH react with the few H+H^+ ions present. Then more of the acetic acid reacts with water, restoring the H+H^+ ion concentration almost to its original value.

C2H5COOH(aq)+H2O(l)C2H5COO(aq)+H3O+(aq)C_2H_5COOH(aq) +H_2O(l)\to C_2H_5COO^-(aq)+H_3O^+(aq)


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