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Answer to Question #155347 in Inorganic Chemistry for Okonji victor
Question #155347
5mol of a mixture of CH4 and C2H6 requires exactly 358.4L of oxygen for complete combustion, determine the percentage of methane in the mixture (GMV =22.4,dm³ at s.t.p
Expert's answer
Mole = 358./4dm3/ 22.4dm3
= 16gmol-1
Total mole = 21gmol-1
Pecentage of methane© = 5gmol-1 /21gmol-1
=0.2%
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