Question #15476
Cr2O3+2Al=2Cr+Al2O3
Calculate the mass of aluminium needed to react with 1 tonne of chromium (iii) oxide.
Calculate the mass of aluminium needed to react with 1 tonne of chromium (iii) oxide.
Expert's answer
Cr2O3 + 2Al = 2Cr + Al2O3
M(Cr2O3) = 152 kg/kmol
M(Al) = 27
kg/kmol
n(Cr2O3) = 1000 kg / 152 kg/kmol = 6.579 kmol
n(Al) = 2n(Cr) =
6.579*2 = 13.158 kmol
m(Al) = n(Al)*M(Al) = 13.158 kmol * 27 kg/kmol = 355.3
kg
M(Cr2O3) = 152 kg/kmol
M(Al) = 27
kg/kmol
n(Cr2O3) = 1000 kg / 152 kg/kmol = 6.579 kmol
n(Al) = 2n(Cr) =
6.579*2 = 13.158 kmol
m(Al) = n(Al)*M(Al) = 13.158 kmol * 27 kg/kmol = 355.3
kg
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