Question

Calculate the framework electrons using Wade's rule B6H6^-2

Answer 1

Total number valence electrons;

$=(5\times B)+(6\times H)+2$

$=(6\times 3)+(6\times 1)+(2)$

$=18+6+2=26$

Number of electrons for each $B-H$ unit$=(6\times 2)=12$

Number of skeletal electrons $=26-12=14$

Number of $SEP=$ $14\over 2$ $=7$

If $n+1=7$ and boron atoms, then $n=6$