Question #15382
Aluminum will react with bromine to form aluminum bromide (Al2Br6). What mass of bromine (g) is needed to form 1.47 mol of Al2Br6?
Expert's answer
3x mol 1.47 mol
2Al+3Br2--->Al2Br6
3x=1.47
x=0.49 mol
2Al+3Br2--->Al2Br6
3x=1.47
x=0.49 mol
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