Question

When the terminal phosphate is cleaved from the adenosine triphosphate molecule, the products are adenosine diphosphate and inorganic phosphate, ATP + H2O ––> ADP + Pi, where Pi stands for the various forms of phosphate that exist at the pH of the particular solution. If the total concentration of Pi is 2.5 x 10–2M, what are the concentrations of the predominant forms of phosphate that exist at pH 7.4?

Answer 1

During the hydrolysis of the atp into adp there is the existence of various forms of phosphates. To check their ph

$Pi =2.5 × 10 ^-2\newline pH = 7.4\newline 7.4 ÷ (2.5 ×10 ^-2)= 2.96 ×10^-2\newline = 2.96 × 10^-2$