Question

"what volume of oxygen will be needed to burn up 8grams of magnesium at room temperature pressure use a chemical equation to support your answer"

Answer 1

$$2 \mathrm{Mg} + \mathrm{O}_2 \rightarrow 2 \mathrm{MgO}$$ $$\nu(Mg) = \frac{8}{24} = 0.33 \mathrm{mol}$$ $$\nu(O_2) = \frac{0.33}{2} = 0.167 \mathrm{mol}$$ $$V(O_2) = 0.167 * 22.4 = 3.73 \mathrm{L}$$ $$V(O_2) = 3.73 \mathrm{L}$$