2C6H5COOH+15O2→14CO2+6H2O2C_6H_5COOH + 15O_2 → 14CO_2 + 6H_2O2C6H5COOH+15O2→14CO2+6H2O
According to the equation above, 2 moles of benzoic acid produces 6 moles of water
0.1 moles of benzoic acid produces x mol of water
x = 0.1×6 / 2 = 0.3 mol
Therefore 0.3 moles of water is produced in the reaction.
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