Answer to Question #148795 in Inorganic Chemistry for Ram Mohan

Question

Aluminium Nitrate reacts with Sod. Hydroxide to form Aluminium Hydroxide. What mass of Aluminium hydroxide will ppt.
When 35.5 ml of 0.145 mol/L aq. Aluminium Nitrate is mixed with 44.2mlof 0.215 mol/L Aq. Sod. Hydoxide? Kindly provide solution)

Answer 1

In this reaction, NaOH is the limiting reagent

Mole of NaOH = 44.2 × 0.01L × 0.215M = 0.009503 mol

Al(NO₃)₃ + 3NaOH = Al(OH)₃ + 3NaNO₃

3 mole NaOH = 1 mole Al(OH)₃ = 78g Al(OH)₃

1 mole NaOH = 78/3 g Al(OH)₃

0.009503 mole of NaOH = 78 × 0.009503/ 3 g Al(OH)₃

= 0.25g Al(OH)₃