Question

In the complete reaction of 18.17 g of sodium with 36.90 g of chlorine, what mass of sodium chloride is formed?

Answer 1

In the complete reaction of 18.17 g of sodium with 36.90 g of chlorine, what mass of sodium chloride is formed?

$$2 \mathrm {N a} + \mathrm {C l} _ {2} \rightarrow 2 \mathrm {N a C l}$$ $$\nu (N a) = \frac {1 8 . 1 7}{2 3} = 0. 7 9 m o l$$ $$\nu \left(C l _ {2}\right) = \frac {3 6 . 9}{7 1} = 0. 5 2 m o l$$ $$\nu (N a C l) = 0. 7 9 m o l$$ $$m (N a C l) = 4 6. 2 1 5 g$$ $$\mathrm {m} = 4 6. 2 1 5 \mathrm {g}$$