E=(h)(c)/λ
h : 6.626 10^-34 c : 3.00 10^8 λ: 655 10^-9
--> ((6.626 10^-34)(3.00 10^8)/ (701 * 10^-9))
=3.03 * 10^-19 J
*The calculated energy is for a single photon. Use the energy per photon and Avogadro's number to find the energy of mole of photons.
3.03 10^-19 J ( 6.022*10^23 photons )
------------------- (-------------------------) = 1.82 *10^5 J/mol <-- answer
Photon ( mol )
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