Answer to Question #143060 in Inorganic Chemistry for Jewel Legaspi

Question

in an evacuated 2.0 liter container, 1.8 moles of N2 and 2.2 moles of H2 are placed. at equilibrium 0.6 M of NH3 are present. solve for Kc

Answer 1

N₂ + 3 H₂ ------------- > 2 NH₃

Initial = 1.8 mole 2.2 mole

Eqillibrium = ( 1.8 - x ) mole ( 2.2 - 3x ) mole 2x mole .

Concentration of NH₃ = 2x / 2 = 0.6 M

Concentration of N₂ = [ N₂ ] = 1.8 - x / 2 = 1.8 - 0.6 / 2 = 0.6 M

Concentration of H₂ = [ H₂ ] = 2.2 - 3 x / 2 = (2.2 - 3 * 0.6 ) / 2 = 0. 2 M

K_c = [ NH₃ ]² / [ H₂ ]^{3 .} [ N₂ ]

K_c = ( 0.6 )² / ( 0.6 ) * ( 0.2 )³ .

K_c = 75 .