Question

What volume (in milliliters) of a 0.635 M NaOH solution contains 8.35 g of NaOH?

Answer 1

$\begin{aligned} &\textsf{mass of }NaOH = 8.35g\\ &\textsf{amount of }NaOH = \frac{8.35}{40} = 0.209mol\\ &\textsf{concentration of }NaOH = 0.635M \end{aligned}$

$Volume = \dfrac{no.\ of\ moles}{concentration}$

$\begin{aligned} Volume =\dfrac{0.209}{0.635}= 0.329dm^3 \end{aligned}$

Volume = $0.329dm^3$ = 0.329L = $0.329× 1000$ mL = 329mL

$\therefore$ The volume (in milliliters) of the solution is 329 mL.