Answer to Question #142292 in Inorganic Chemistry for Sarita bartwal

Question

Draw the MO energy level diagram of NO and calculate its bond order

Answer 1

Electronic configuration of nitrogen is 1s2 2s2 2p3

Electronic configuration of oxygen is 1s2 2s2 2p4

Thus, total number of electrons present in molecule is 15

The molecular orbital energy-level diagram of molecule is as follows

Bond order =1/2(no. of BMO-no. of anti ABMO)

For NO total no.of electron=15

no. of anti bonding electron=5

no. of bonding electron=10

1/2(10–5)=2.5