Bond order=2
(No. of electrons in bonding orbital)−(No. of electrons in anti−bonding orbital)
Bond order of N2=6/2 =3
=3⇒N≡N
Bond order of O2
=2
=2⇒O≡O
If orbitals contains unpaired electrons, it is paramagnetic. Otherwise diamagnetic.
N2
does not have unpaired electrons. So, it is diamagnetic.
O2
have 2 unpaired
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