Answer to Question #141934 in Inorganic Chemistry for Olebogeng

Question #141934

Describe the bonding in both the superoxide ion (O2-) and the peroxide ion (O22-) in terms of molecular orbital theory, and compare their bond order to that of O2

Expert's answer

Bond order of the following is: O22−=1,O2−=1.5,O2=2,O2+=2.5

Learn more about our help with Assignments: Inorganic Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. Using specific examples of a homonuclear and heteronuclear diatomic molecule, highlight the differen
2. For early period homonuclear diatomic molecules, the 2π orbitals are lower in energy than the 2σ o
3. A Copper(II) octahedral complex shows 4 bonds of length 240 pm and 2 bonds of length 318 pm. Explain
4. In the formation of CO, the 2s orbital from C and 2p orbital from O could also participate in the fo
5. Answer the problem using the rubrics below as a guide: Given and Asked - 3 pts; Complete data and pr
6. Answer the problem using the rubrics below as a guide: Given and Asked - 3 pts; Complete data and p
7. Answer the problem using the rubrics below as a guide: Given and Asked - 3 pts; Complete data and p

Who Can Help Me with My Assignment

There are three certainties in this world: Death, Taxes and Homework Assignments. No matter where you study, and no matter…
How to Finish Assignments When You Can’t

Crunch time is coming, deadlines need to be met, essays need to be submitted, and tests should be studied for.…
How to Effectively Study for a Math Test

Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…

Answer to Question #141934 in Inorganic Chemistry for Olebogeng

Bond order of the following is: O22−​=1,O2−​=1.5,O2​=2,O2+​=2.5

Comments

Leave a comment

Related Questions

Bond order of the following is: O22−=1,O2−=1.5,O2=2,O2+=2.5