Question

a) draw the boron-haber cycle of NaCl
b) draw the mo energy level diagram of NO and calculate it's bond order.

Answer 1

Bond order =1/2(number of BMO – number of anti ABMO)

For total number of electron =15

Number of anti bonding electron = 5

Number of bonding electron =10

1/2(10 – 5) = 2.5

This is how we get bond order as 2.5