KP=K_P=KP= PNH3PN2PH2P_{NH_3}\over P_{N_2}P_{H_2}PN2PH2PNH3
KPK_PKP for reverse react ion reaction=== 1Kp1\over K_pKp1
=== 14.34×10−3(100°C)1\over 4.34\times 10^{-3}(100°C)4.34×10−3(100°C)1
=230.414=230.414=230.414
∴\therefore∴ KpK_pKp for reverse reaction=230.414=230.414=230.414
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments